If one end of a diameter of a circle is (2,3) and the centre is (-2,5),find the other end of the diameter
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The midpoint formula is (x1+x2)/2 , (y1+y2)/2
Centre is the mid point of the diameter.
so, (2+x)/2 , (3+y)/2 = (-2,5)
then (2+x)/2 = -2 and (3+y)/2 = 5
2+x = -4 3+y = 10
x=-6 y = 7
therefore the other of the diameter is (-6,7).
Centre is the mid point of the diameter.
so, (2+x)/2 , (3+y)/2 = (-2,5)
then (2+x)/2 = -2 and (3+y)/2 = 5
2+x = -4 3+y = 10
x=-6 y = 7
therefore the other of the diameter is (-6,7).
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