If one end point of a diameter of a circle having centre at (1, 2) is (2, -1), the other end point is ……..
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Step-by-step explanation:
Given:
A(2,-1) and B(x,y) and centre c=(1,2)
{centre c=[(x1+x2)/2 , (y1+y2)/2] }
(1,2)=[(2+x))2 , (-1+y)/2]
1=(2+x)/2 , 2=(-1+y)/2
2=2+x , 4=-1+y
x=2-2 , y=4+1
x=0,y=5
B=(x,y)=(0,5)
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