If one equation of a pair of dependent linear equations is -3x+5y-2=0. The second equation will be:
6x+10y-4=0
6x-10y-4=0
6x+10y-4=0
-6x+10y+4=0
Answers
Answer:
in the equation -3x+5y-2=0.let A1=-3,B1=5,C1=-2
We have A1/A2=B1/B2=C1/C2=1/k
wher k is the arbitrary constant.
by substituting the values we get
-3/A2=5/B2=-2/C2=1/k
we get A2=-3k,B2=5k,C2=-2k
put c=-2
we get A2=6,B2=-10,C2=4
so the second linear equation is 6x-10y+4=0
or we will get -6x+10y-4=0 if we put k=2
so there is no correct option
Given : one equation of a pair of dependent linear equations is -3x+5y-2=0
To Find : The second equation will be:
Solution :
Pair of linear equations
a₁x + b₁y + c₁ = 0
a₂x + b₂y + c₂ = 0
Consistent
if a₁/a₂ ≠ b₁/b₂ (unique solution and lines intersects each others)
a₁/a₂ = b₁/b₂ = c₁/c₂ (infinite solutions and line coincide each other )
Inconsistent
if a₁/a₂ = b₁/b₂ ≠ c₁/c₂ ( No solution , lines are parallel to each other)
a pair of dependent linear equations Means a consistent system with Infinite solutions Hence
a₁/a₂ = b₁/b₂ = c₁/c₂ = k
So one of the Equation can be obtained by multiplying other equation with a non zero real number
-3x+5y-2=0
Multiply it by 2
-6x + 10y - 4 = 0 ( no such option given)
-3x+5y-2=0
Multiply it by -2
6x - 10y + 4 = 0 ( no such option given)
None of the given options is correct
as option 1 and 3 are same so possible that one of the option is
-6x + 10y - 4 = 0
Hence correct option would be -6x + 10y - 4 = 0
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