Question

If one factor of x^3 +7 Kx 2 - 4kx
+12 18 (2+3) the de voluego k is​

Answer 1

Answer:

k = 1/5

Step-by-step explanation:

x³ + 7kx² - 4kx + 12

If (x + 3) is a factor

then substituting (x = -3) into the equation will return us zero.

Solve k:

(-3)³ + 7k(-3)² - 4k(-3) + 12 = 0

-27 + 63k + 12k + 12 = 0

75k - 15 = 0

75k = 15

k = 1/5