Question

If one gram of substance is fully
converted into energy, how much
energy
will be produced
(c = 3x108m/sec)?
​

Answer 1

SOLUTION

GIVEN

One gram of substance is fully converted into energy

TO DETERMINE

The energy will be produced

FORMULA TO BE IMPLEMENTED

If m is the mass of a substance and c is the speed of light then the energy produced = E = mc²

EVALUATION

Here the mass of the substance = m =

= 1 gram

$\sf{ = {10}^{ - 3} \: \: kg}$

$\sf{Now \: speed \: of \: light = c = 3 \times {10}^{8} \: m {s}^{ - 1} }$

Hence the energy produced = E =

$\sf{ = {10}^{ - 3} \times {(3 \times {10}^{8}) }^{2} } \: \: Joules$

$\sf{ = {10}^{ - 3} \times 9 \times {10}^{16} } \: \: Joules$

$\sf{ = 9 \times {10}^{16 - 3} } \: \: Joules$

$\sf{ = 9 \times {10}^{13} } \: \: Joules$

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Answer 2

Answer:

$\huge\bf\red{\underline{\underline{aNswER}}}$

Explanation:

GIVEN

One gram of substance is fully converted into energy

TO DETERMINE

The energy will be produced

FORMULA TO BE IMPLEMENTED

If m is the mass of a substance and c is the speed of light then the energy produced = E = mc²

EVALUATION

Here the mass of the substance = m =

= 1 gram

\sf{ = {10}^{ - 3} \: \: kg}=10

−3

kg

\sf{Now \: speed \: of \: light = c = 3 \times {10}^{8} \: m {s}^{ - 1} }Nowspeedoflight=c=3×10

8

ms

−1

Hence the energy produced = E =

\sf{ = {10}^{ - 3} \times {(3 \times {10}^{8}) }^{2} } \: \: Joules=10

−3

×(3×10

8

)

2

Joules

\sf{ = {10}^{ - 3} \times 9 \times {10}^{16} } \: \: Joules=10

−3

×9×10

16

Joules

\sf{ = 9 \times {10}^{16 - 3} } \: \: Joules=9×10

16−3

Joules

\sf{ = 9 \times {10}^{13} } \: \: Joules=9×10

13

Joules

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