Question

If one gram of sulphur contains x atoms, calculate the number of atoms in one gram of oxygen element, (Atomic masses S = 32 u ; O = 16 u)

Answer 1

Answer:

32 g of S = 1 mole

So, 1 g of S = 1/32 mole

Now since equal moles of all the substances contain equal number of atoms so, 1/32 mole of oxygen will also contain x atoms like S.

16 g of oxygen = 1 mole

So, 1 g of oxygen = 1/16 mole

Now, 1/32 mole of oxygen contains = x atoms

So, 1/16 mole of oxygen will contain = x × 32/16 = 2x atoms.

Answer 2

Explanation:

Carbon’s gram atomic mass = 1 mole of sulphur = 32 gram .

So, 1 mole = 32 gram of sulphur .

Thus, Sulphur of 1 mole $=\frac{1}{32} \text { mole }$.

So, x atoms are present in $\frac{1}{32} \text { mole }$ of sulphur elements.

And, x atoms are present in $\frac{1}{32} \text { moles }$ of oxygen as well.

Oxygen of 1 mole = 16 grams, which is $\frac{1}{16} \text { mole }=1$ gram of oxygen.

Thus, $\frac{1}{16}$ oxygen moles has $x \times 2$ atoms.

So, 1 gram of sulphur $=\frac{1}{32} \text { mole }.$

Now subsequently equal moles of all the constituents comprise equal atom number so, $\frac{1}{32} \text { mole }$ of oxygen will also include x atoms like Sulphur.