If one gram of sulphur contains x atoms calculate the number of atoms in 1 gram of oxygen element
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32 g of Sulphur → 6.023*10²³ atoms
1 g of Sulphur → 6.023*10²³/32 atoms = x atoms
16 g of Oxygen → 6.023*10²³ atoms
1 g of Oxygen → 6.023*10²³/16 atoms = 2*x atoms
∴No of atoms in 1 g of oxygen = 2x atoms
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Answer:
1 g of Sulphur = x atoms
We know that,
32 g of Sulphur = 6.022*10^23 atoms
= 1g of Sulphur = (6.022*10^23)/32 = x atoms
= 1g of Sulphur = (6.022*10^23) = 32x atoms
Now,
16 g of Oxygen = 6.022*10^23 atoms
Since,
6.022*10^23 atoms = 32x atoms
Therefore, 16 g of Oxygen = 32x atoms
Hence,
1 g of Oxygen = 2x atoms
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