Question

if one integer is greater than the other by 3, the difference of their cubes is 117, what could be their sum​

Answer 1

Answer:

Homogeneous mixtures are uniform or consistent in their phase and composition. In a homogeneous mixture, the elements forming the mixture do not remain physically distinct. On the other hand, heterogeneous mixtures are not uniform or consistent in their phase and/ or composition. The elements forming the mixture remain physically distinct.

Both the ice and the water are H2O, but they are in two different phases.

A homogeneous mixture has the same uniform appearance and composition throughout, and as is plainly visible in the case of the ice/water mixture, its composition is not uniform.

Ice and water are not actually the same thing, as demonstrated by the fact that we use the two different words "ice" and "water" to describe them.

If all the ice were to melt and there were no impurities present, it would not be a mixture at all but would just be the compound H2O.

This means it is not possible to have a homogeneous mixture of ice and water, because if you "dissolve" the ice in the water it is not actually an aqueous solution, but a pure liquid.

Answer 2

If one integer is greater than another integer by 3, and the difference of their cubes is 117, what could be their sum?

A. 15

B. 7

C. 3

D. 2

E. 1

Spoiler: OA

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Most Helpful Community Reply

abby17

Jan 26, 2012

Let the two integers be 'a' and 'b'

Then, according to the question

a-b=3 and =117

Now

Substituting the values of (a-b) and we get

= 117 - 3ab

27 = 117 - 3ab

9ab=90

ab=10

Now to find the value of (a+b) use

Again substitute the values

(a+b)=

(a+b)=

(a+b)=7

So the answer is B

Step-by-step explanation:

hope it's helpful to you ❤️☺️