If one interior angle of polygon 120 degrees has sides
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The interior angle of the polygon is 120°.
The formula to find the interior angle of a polygon is 180(n-2)/n where n is the number of sides of the polygon.
So, 180(n-2)/n = 120
Solving the equation,
180n - 360 = 120n
180n - 120n = 360
60n = 360
n = 6
Therefore, polygon has 6 sides.
Hope it helps.
The formula to find the interior angle of a polygon is 180(n-2)/n where n is the number of sides of the polygon.
So, 180(n-2)/n = 120
Solving the equation,
180n - 360 = 120n
180n - 120n = 360
60n = 360
n = 6
Therefore, polygon has 6 sides.
Hope it helps.
Answered by
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the polygon has 6 sides.
180(n-2)/n = 120
180n - 360/n = 120
180n - 360 = 120n
180n - 120n = 360
60n = 360
n = 6.
180(n-2)/n = 120
180n - 360/n = 120
180n - 360 = 120n
180n - 120n = 360
60n = 360
n = 6.
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