Math, asked by Jayadeepak, 8 months ago

If one is a Zero of polynomial
ax^2-3(a-1)x-1 then value of a​

Answers

Answered by riya1303
1

Answer:

1 is a zero of ax2-3(a-1)x-1, we have a-3(a-1)-1=0.

Step-by-step explanation:

Answered by himanshurai54
0

Answer:

Given:

p(x)=ax ^2−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1

Step-by-step explanation:

Hopefully do u like that

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