Question

if one is a zero of polynomial p{x} = ax^2-3{a-1}x-1 then find the value of a

Answer 1

Answer:

Step-by-step explanation

P(x)=ax^2-3(a-1)-1

P(x)=ax^2-3a+3-1=ax^2-3a+2

P(1)=0 as 1 is a root ( applying factor theroem )

P(1)=a(1)^2-3(1)+2=0

P(1)=a-3+2=0

P(1)=a-1=0

P(1)=a=1

Hence a is 1