if one is a zero of the polynomial p(x)=ax^3-3 (a-1)x. Then find the
value of a'.
answer me plsszzz...
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if 1 is a zero of poly. p(x)=ax^3-3(a-1)x then
p(1)=0
p(1)=a×1^3-3(a-1)×1
0=a-3(a-1)
0=a-3a+3
0=(-2a)+3
2a=3
a=3/2
so the value of a if 1 is a zero of poly. p(x)=ax^3-3(a-1)x is 3/2.....
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p(1)=0
p(1)=a×1^3-3(a-1)×1
0=a-3(a-1)
0=a-3a+3
0=(-2a)+3
2a=3
a=3/2
so the value of a if 1 is a zero of poly. p(x)=ax^3-3(a-1)x is 3/2.....
HOPE THIS WILL HELP YOU
PLZ MARK IT AS BRAINLIEST
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