Question

if one is one of the zeros of the polynomial p x is equal to x square - bx + 1 then (a) a+1=b (b) a-b=0 (c) a-b-1=0 (d) a+b=1​

Answer 1

Step-by-step explanation:

Given: p(x)=ax

2

−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1