Question

if one is the zero of the polynomial 2x²+3x²+x+d then d=​

Answer 1

Answer:

2x²+3x²+x+d=5x²+x+d

p(1)=5×1²+1+d=0

5+1+d=0

6+d=0

d= -6

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Answer 2

Answer:

d = -14 and (^2 = Square)

Step-by-step explanation:

2x^2 + 3x^2 + X + d = 0

by applying 1 in the place of x,

2(1)^2 + 3(1)^2 + (1) + d = 0

4 + 9 + 1 + d = 0

14 + d = 0

d = 0-14

d = -14