if one is the Zero of the polynomial ax square - 3 into a minus 1 into x minus 1 find the value of a
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I didn't fully get the language but I assume that this will be the answer if my equation is wrong please tell me.. I'll change the answer
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Step-by-step explanation:
P(x)=ax^2 -3(-1)x-1
P(1)=a(1)^2 +3(1)-1
a +3 -1 =0
a= 1+3
a= -2
( I was not sure about equation. Is it correct ?)
suhanasudheer:
I got it as 1
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