Question

If one leg of a triangle is 4 feet and the other leg is 12 feet, what is the hypotenuse?

Answer 1

GIVEN :-

In right triangle ABC

AB = 4 feet

BC = 12 feet

TO FIND :- Hypotenuse AC

SOLUTION :-

${perpendicular}^{2} + {base}^{2} = {hypotenuse}^{2}$

[By pythagoras Theorem]

AC =

$\sqrt{{4}^{2} + {12}^{2} } \\ \\ = \sqrt{16 + 144} \\ \\ = \sqrt{160} \\ \\ = \boxed {12.65}$

THEREFORE, the hypotenuse is 12.65 feet.