if one longest side of a right angle triangle is 7cm then find the other two sides
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Let one side be x
Then the other side will be,
x + 7 + other side = 180
Therefore, other side = 180 - x - 7 = 173 - x
Using Pythagoras theorem,
ie sum of squares of the legs = square of hypotenuse
In a right angled triangle, the longest side is the hypotenuse.
Therefore, hypotenuse = 7cm
Then,
x^2 + (173 - x) ^2 = 7^2........(Pythagoras Theorem)
x^2 + 173^2 + x^2 - 2*173*x = 49.....(expanding (173 - x) ^2 using the identity (a-b) ^2 = a^2 +b^2 - 2ab)
2x^2 + 29929 - 346x = 49
2x^2 + 29929 - 49 - 346x = 0
2x^2 + 29880 - 346x = 0
x^2 - 173x + 14940 = 0
Now u just have prime factorise the above equation to get the value of x.
Then one side will be x and the other side will be 173 - x
Hope this helps...!
#Cheers
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