if one member of a pythagorean triplet is 2m, then the other two members are a)m,m²+1 b)m²+1,m²-1 c)m²,m²-1 d)m²,m²+1
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Let a=m
2
−1
b=2m
c=m
2
+1
using pythagoras theorem, a
2
+b
2
=c
2
So, (m
2
−1)
2
+4m
2
=(m
2
+1)
2
m
4
+1−2m
2
+4m
2
=(m
2
+1)
2
m
4
+2m
2
+1=(m
2
+1)
2
(m
2
+1)
2
=(m
2
+1)
2
Since LHS=RHS , we can say that a,b,c always form pythagorean triplet.
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