Question

if one member of Pythagorean triplet is m2+1 then other two members are ________​

Answer 1

Step-by-step explanation:

We know that, for any natural number m greater than 1, (2m, (m²-1), (m²+1)) is a pythagorean triplets.

So,

One number is 2m

Then other numbers are (m²+1) and (m²-1)

Let us take an example to understand.

One number be 4

The the pythagorean triplet,

2m = 4

\implies⟹ m= 2

m²+1 = 2²+1 = 4+1 = 5

and

m²-1 = 2²-1 = 4-1 = 3

Now,

3² + 4² = 5²

9 + 16 = 25

So,

(3,4,5) are pythogorean triplets.

Answer 2

Answer:

m²-1 , 2m (the smallest even number)

Step-by-step explanation:

According to Pythagorean triplet, if a, b and c are integer then,

(2m, m²+1,m²-1) where 2m is the smallest even number among them. Find m from it . Then find

m²+1,m²-1 .

For example:-

(10,26,24)

= 2m = 10

= m = 10/2

= m = 5

Now, m²+1 = 5²+1 = 25+1 = 26

m²-1 = 5²-1 = 25-1 = 24

Hence, (10,26,24) is a Pythagorean triplet.

I hope it help you.