If one mole of a gas A (mol.wt-40) occupies a
volume of 20litres, under the same conditions of
temperature and pressure the volume occupied by
2 moles of gas B (mol.wt=80) is
1) 80 L
2) 60 L
3) 50 L
4) 40 L
Answers
Answered by
21
Answer:
80 l
Explanation:
calculate mass of gas A using formula mole=mass/molar mass
thus, gas A's mass = 1 x 40 = 40gm
similarly, gas B's mass = 2 x 80 = 160gm
now,
if 40 gm gas occupies 20L
then 160gm occupies - x
using unitary method,
x = 20/40 x 160
= 80 L
Answered by
8
- for 1 mole of 40 gm it is 20 .in quation asking for 2moles of 80 gm gas occupies ___volume.
- ans is 80 L
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