If one mole of a monatomic gas (γ = 5/3) is mixed with one mole of a diatomic gas (γ = 7/3), the value of g for the mixture is(a) 1.40(b) 1.50(c) 1.53(d) 3.07
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Answer:
B) 1.50
Explanation:
For monoatomic gas -
Cv = 3/2RT
Cp = 5/2RT
For diatomic gas -
Cv = 5/2RT
Cp = 7/2RT
Thus for mixture of 1 mole each will give -
Cv = 3/2RT+5/2RT/2
Cp=5/2RT+7/2RT/2
Cp/Cv = 3RT/2RT
= 1.5
Thus, the value of g for the mixture is 1.5
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