Question

If one mole of a monoatomic gas is mixed with one moole of a diatomic gas then the value of gamma for the mixture is

Answer 1

⭐⭐⭐ Hey mate!!⭐⭐⭐

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❄️⚡First of all find Cp mix and Cv mix

❄️⚡Then apply formula gamma mix = Cpmix/Cv mix

Here you go...

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❄️Consider ( u = mu=no° of moles)

❄️Cp mix = u1Cp1 + u2Cp2 ÷u1+u2.....(1)

Given,

❄️u1 =1 mole and u2=1mole

❄️Cp1 for monoatomic gas = 5/2R

❄️Cp2 for diatomic gas = 7/2R

❄️⚡Putting these value in equation (1) you will get .

❄️Cp mix = 5/2R +7/2R ÷ 2 =3R

Now ,

❄️Cv mix =u1 Cv1 + u2Cv2 ÷2

❄️Cv1 for monoatomic gas = 3/2R

❄️Cv2 for diatomic gas= 5/2R

⚡Cv mix = 2R

Now,

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Coming to your question

⚡⚡Gamma mix = Cp mix /Cv mix

= 3R/2R

=1.5⚡⚡

Hope it will help you...✌️✌️

#phoenix⭐