Question

if one mole of an ideal gas at constant temperature changes its pressure from 5 atm to 2 atm and volume from 4L to 10L, then enthalpy change will be​

Answer 1

Answer:

-18

Explanation:we know that, ΔH = ΔU+PΔV

Given, at const. temp ⇒ isothermal process ⇒ ΔU=0

so,  ΔH=PΔV

ΔH = (2-5)(10-4)

     = -3×6

     = -18

i guess

Answer 2

Answer:

zero

Explanation:

hope it helped. ........