Question

If one mole of an ideal gas at STP is heated through 1 K, the work done by the gas will be

Answer 1

Explanation:

W = 0, q = 5.46 kJ

W = 0,q=0

W = -5.46kJ, q = 5.46 kJ

W=5.46kJ, q = 5.46 kJ

Solution :

W=PΔV=P×0=0

Q=CV(ΔT)=20×273=5460J=5.46kJ

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Answer 2

Given:   $n=1$ mole $T=1K$

           Since at constant temperature and pressure, the ideal gas equation is,

             $PV=nRT$

where P is pressure, V is volume and R is the ideal gas constant

               $R=8.314 \frac{J}{mol\times k}$

Work done by gas will be

                  $W=nRT$

        $W=1\times 8.314\times 1$

                $=8.314Joule$

Hence the work done by gas will be 8.314 joule

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