Question

If one mole of oxygen atoms weighs 16 grams, find the mass of one atom of oxygen in (grams). [ Please answer with explanation]

Answer 1

Given:

One mole of oxygen atoms weighs 16 grams

To find :

Find the mass of one atom of oxygen in (grams)

Theory :

Mole: Mole  is a unit which represents

 particles of the same nature.

$\star$ Note :

The number $\sf6.023\times10^{23}$ is call Avogadro number $\sf\:N_{a}$

• Important points :

1 mole = $\sf6.023\times10^{23}$ particles

1 mole of atoms = $\sf6.023\times10^{23}$ atoms

1 mole of molecules=$\sf6.023\times10^{23}$ molecules

1 mole of electrons=$\sf6.023\times10^{23}$ electrons

Solution :

Mass of 1 mole of oxygen= 16 gm

We know that:

1 mole of oxygen contains =  atoms

Thus,

Mass of  oxygen atoms = 16 gm

• By unitary unit

Mass of 1 oxygen atom =$\sf\dfrac{16}{6.023\times10^{23}}$ gm

Mass of 1 oxygen atom =$\sf\dfrac{16}{6.023}\times10^{-23}$ gm

Mass of 1 oxygen atom =$\sf\dfrac{16}{6.01}\times10^{-23}$ gm

Mass of 1 oxygen atom =$\sf2.66\times10^{-23}$gm

• Extra information :

Mole= $\frac{weight\ of\ compound ( gm)}{gram\ molecular\ mass}$

Mole = $\frac{weight\ of\ element}{gram\ atomic\ mass}$

Mole = $\frac{number\ of\ particles}{avogadro\ number}$

Mole= $\frac{volume (l)}{ 22.4(l)}$

Answer 2

Explanation:

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