Question

If one natural number is 4 times another and their sum is 65 . find the number​

Answer 1

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Sum of the two numbers = 65

• One natural number is 4 times other.

$\;\;\underline{\textbf{\textsf{ To Find :-}}}$

• The required numbers

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

Let the one number be x

Given that,

One natural number is 4 times other.

Then , the other number will be = 4x

Again, it’s given that

• Sum of the two numbers = 65

Then,

$\dashrightarrow {\sf{Sum = 65}} \\ \\ \dashrightarrow {\sf{x + 4x= 65}} \\ \\ \dashrightarrow {\sf{5x= 65}} \\ \\\dashrightarrow {\sf{x= \cancel{\dfrac{65}{5}}}}$

$\bf{ ⇢ x = 13 }$

$\underline{\textsf{ The other number is \textbf{ 52}}}.$

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$\\ \underline{ \bigstar \textsf{Let's check the answer :- }}$

Here,

• Sum of the two numbers = 65

• One number = 13

• Other number = 52

$\\ \underline{ \bigstar \textsf{Substitute given the values : }}$

$\dashrightarrow {\sf{Sum = 65}} </p><p></p><p>\\ \\\dashrightarrow {\sf{13+52= 65}} \\ \\ \dashrightarrow {\sf{65= 65}}$

$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\therefore{ \underline {\bf{Verified}}}$

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Answer 2

Answer:

Let one natural number be x.

x + 4x = 65

x = $\frac{65}{5}$

x = 13.

4x = 52

Therefore the two natural numbers are 13 and 52.

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