if one number exceeds the other numbers by 15 and their sum is 95 find the two numbers
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Answered by
2
Answer:
my friend here is your answer
Let the bigger number be x and smaller number be $y$$
Given, x+y=95 ....(1)
Also given, x−y=15 ....(2)
∴x=15+y ....(3)
Substitute this value of x in equation (1), we get
15+y+y=95
⇒15+2y=95
⇒2y=95−15
⇒2y=80
⇒y=40
Put the value of y in equation (2), we get
x−40=15
⇒x=40+15=55
Therefore, the two numbers are 40 and 55.
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Answered by
1
Answer:
one is 40 and other is 55.
Step-by-step explanation:
95-15=80
=80÷2=40
:: one number is 40.
other number =
95-40=55
:: the second number is 55.
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