If one number is thrice the other and their sum is 96, find the numbers. The answer should be 24 and 72
Answers
Hii mate...
Step-by-step explanation:
Given That : the sum of two number is 96 and one is thrice to other
so let the number be 'x'
so according to Question the second number will be '3x'
Now,
x + 3x = 96
4x = 96
x = 96/4
x = 24
Second number = 24×3= 72
Additional information
More Questions like this
1. The sum of the digit of a 2- digit number is 11 the number obtained by interchanging the digits exceeds the original number by 27 find the number
Solution :
Let the unit place digit be x
So , ten's place digit = (11 - x)
Original number = x+10(11-x)= x +110-10x= -9x +110
New number obtained by reserving the digits =
10x + 11 - x = 9x +11
A.T.Q
= (9x + 11) - (-9x + 110) = 27
= 9x + 11+9x -110 = 27
= 18x - 99 = 27
= 18x = 99+27
= 18x= 126
= x = 7
therefore,
Unit place digit = 7 and Ten's place digit= 11-7
Hence the required number = 7 + 4 × 10 = 47
2. The sum of three consecutive multiple of 7 is 777 Find these multiples
Solution :
Let the three consecutive multiple of 7 be x , x+7 and x+14
So,
= x + x + 7 + x + 14 = 777
= 3x + 21 = 777
= 3x = 777 -21
= 3x = 756
= x = 756/3 = 252
Hence the required multiples are 252,252+7= 259+7=266
Facts that matter
• An algebraic equation is an equality involving variables Here we will deal with the equations having only one variable eg. 3x +5 = x+3
• The algebraic equations with one variable are called as linear equations
Hope the answer will be helpful for you mate
keep smiling always ☺️
have a wonderful day ahead...
Answer:
24 & 72
Step-by-step explanation:
let the first number be x
so second number = 3x
given
x + 3x = 96
=> 4x = 96
=> x = 96/4 = 24
so first number = 24
&
second number = 3 × 24 = 72
& difference = 48
=> 72 - 24 = 48 Satisfies