if one number of a pythogram triplet is 8 then the other 2 members are a.7&10 b.5&6 c.10&11 d.6&10
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As we know 2m, m
2
+1,m
2
−1 form a Pythagorean triplet for any number m>1.
Let us assume 2m=8
⇒m=4
Therefore, m
2
+1 = 4
2
+1
⇒16+1=17
and m
2
−1 = 4
2
−1
⇒16−1=15
Hence, the other two members are 15 and 17.
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Answer:
two numbers are 15 plz mark it as braniest
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