Question

If one of a parallelogram is 24degree less than twice the smallest angle then the largest angle of the parallelogram is?

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Answer 1

Answer:

Since it is a parallelogram the sum of adjacent angles = 180°

Let the smallest angle of the parallelogram=x°

Then the other angle=(2x-24)°,

x °+(2x-24)° =180°

x=68°

And the second angle= 2*68–24=112°

So the largest angle is 112° .

Answer 2

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$\bf{\underline{Given}}$

If one angle of parallelogram is 24° less than twice the smaller angle

.

$\bf{\underline{To find :-}}$

The largest angle of parallelogram

$\bf{\underline{Solution :-}}$

Let the smallest angle be x

and largest angle be 2x - 24°

we know that,sum of adjacent angle of a parallelogram is 180°.

Now,

According to the above values,

x + 2x - 24° = 180°

⤇ 3x - 24° = 180°

⤇ 3x = 180° + 24°

⤇ 3x = 204°

⤇ x = 204/3

⤇ x = 68°

Then,

⤇ 180° - 68°

⤇ 112°

Hence,the largest angle of the Parallelogram wil be 112°.