if one of a triangle is 80° and the other two angles are in the ratio 3:7 . find the angles
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ab and cd or 80 cm ki arc and middel me 7 or upper me 3
Answered by
1
Answer:
Let the <B be 3x
<C be 7x
using the angle sum property,
<A+<B+<C = 180 degree
80+3x+7x = 180 degree
80+10x = 180 degree
10x = 180-80 = 100 degree
10x = 100 degree
x = 100/10 = 10 degree
So, the second angle is 3x = 10*3 = 30
the third angle is 7x = 10*7 = 70
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