Question

if one of the angle of a triangle is 110°, then find the angle between the bisectors of the other two angles​

Answer 1

Answer:

Let angle A be 110

and angle B be 2a

So angle C will be 180–110–2a ———angle sum

Angle C is 70–2a

Let angle between 2 angle bisectors be x

Assuming the bisector is internal angle bisector

2a÷2 + (70–2a)÷2 + x =180

x=180-a - (35-a)

Solving, we get x = 155°

Please note : that this answer is assuming that you understood the question correctly or i could have helped and put photos but i am too lazy if you did not understand i am free to help XD...

Answer 2

Answer:

Let angle A be 110

and angle B be 2a

So angle C will be 180–110–2a ———angle sum

Angle C is 70–2a

Let angle between 2 angle bisectors be x

Assuming the bisector is internal angle bisector

2a÷2 + (70–2a)÷2 + x =180

x=180-a - (35-a)

Solving, we get x = 155°

Step-by-step explanation: