Question

If one of the angles of a triangle is 130 then find angle between the bisectors of other two angles

Answer 1

Given:-
$<b>$
One of the angle of a triangle=)<130°

Bisect in two angle then must be divided by 2


1/2×50

1×25

25°


Using Formula:-


Sum of all Triangle measure=)180


Required angle=x°


x+25°=180°

x=180°-25°


x=155°

Answer 2

in a triangle ABC let angle A = 130 then angle B+Angle C = 50
1/2( angle B + angle C ) = 25
let bisectors meet at p then
1/2 ( angle B + angle C) + angle p = 180
angle p = 180-25= 155