if one of the diagonal of a trapezium divides the other in the ratio 2:1 prove that one of the parallel sides is twice the other
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Given: ABCD is a trapezium. AB||CD. Diagonal BD divides the diagonal AC in the ratio 1:2 at O. i.e. OA: OC = 1:2.
To prove: CD = 2 AB
Proof: In ∆ AOB and ∆COD
∠AOB = ∠COD (Vertically opposite angles)
∠ABD = ∠ODC (Alternate angles)
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Given: ABCD is a trapezium. AB||CD. Diagonal BD divides the diagonal AC in the ratio 1:2 at O. i.e. OA: OC = 1:2.
To prove: CD = 2 AB
Proof: In ∆ AOB and ∆COD
∠AOB = ∠COD (Vertically opposite angles)
∠ABD = ∠ODC (Alternate angles)
Hope It's Help You...
Please mark in brain list
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