Math, asked by soniabansal1244, 5 days ago

If one of the diagonals 18 32 cm,
4. Find the area of a rhombus if each of its sides measures 41 cm and one of the diagonals is 80 cm.
5. The area of a rhombus is 210 cm. If one of its diagonals is 14 cm, then find its other diagonal.

Answers

Answered by ashu2tosh4tiwari7
0

Answer:

4=720

Step-by-step explanation:

A=pq

2

a=p2+q2

2

Solving forA

A=1

2p4a2﹣p2=1

2·80·4·412﹣802=720

Answered by ak00008601
0

Answer:

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Step-by-step explanation:

In a rhombus, the diagonals bisect each other at 900

Referring the diagram, if PR =18cm,  SQ =24cm, then OP =9cm,  OQ =12cm

Since, triangle POQ is a right angled triangle,

PQ2=OP2+OQ2=>92+122=225

PQ=225=15 cm

Hence, the length of the sides of the diagonal =15 cm.

Since the length of all sides of a rhombus are equal, Perimeter =4× length of one side =4×15=60cm

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