Question

If one of the enantiomers of 2-methylbutan-1-ol have specific rotation of +5.9, then the specific rotation of other enantiomer will be

Answer 1

Explanation:

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A sample of 2-butanol has a specific rotation of -9.75 degrees. Determine the % ee (enantiomeric excess) and the molecular composition of this sample. The specific rotation of pure (+)-2-butanol is +13.0 degrees.

Answer 2

Answer:

- 5.9 is the specific rotation for the enantiomer of  2-methylbutan-1-ol .

Explanation:

Specific rotation is the change in orientation of plane-polarized monochromatic light when it is passed through the compound in a solution.

Enantiomers are mirror images of each other that is why they rotate the plane polarized light by same amount but just in opposite direction.