If one of the equation
![( {p}^{2} + 2) {x}^{2} + 13x + 3p = 0 ( {p}^{2} + 2) {x}^{2} + 13x + 3p = 0](https://tex.z-dn.net/?f=%28+%7Bp%7D%5E%7B2%7D++%2B+2%29+%7Bx%7D%5E%7B2%7D++%2B+13x+%2B+3p+%3D+0)
is the reciprocal of the other, then find the value of p.
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Answer:
let the roots be alpha and beeta then solve
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