If one of the exterior angles of a parallelogram is 40 degrees , the interior angles are ______
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Given, ∠ C = 110
o
,∠ADE=40
o
∠ D=∠B {Opposite angle}
Also,
∠D+∠C=180
o
{because these interior angles lie on the same side of the transversal}
∠D=180
o
−110
o
=70
o
Therefore,
∠ EDC=∠D−∠ADE=70
o
−40
o
=30
o
∠ EBC=∠B=70
o
, ∠ DCB=110
o
Therefore,
∠ BED=360
o
−110
o
−70
o
−30
o
=150
o
{Sum of angle of quadrilateral EBCD = 360
o
}
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