if one of the factor of polynomial (X)= X² + X - 6 is x-2,then the value of other factor is:
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The value of the other factor is (x+3)
Given:
Polynomial p(x)= x² + x - 6
One of the factor is x-2
To find:
The value of other factor
Solution:
Given Polynomial p(x)= x² + x - 6
Given one its factor is x-2
To find the factors of p(x) do the factorization as given below
p(x)= x² + x - 6
Split x as 3x - 2x [ ∵ 3 × - 2 = -6 ]
⇒ x² +3x - 2x - 6
⇒ x (x+3) -2(x+3)
⇒ (x+3)(x-2)
The factors of given p(x) are (x+3)(x-2)
Therefore, the value of the other factor is (x+3)
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