Question

If one of the factor of 
${x}^{2} + x - 20 \: is(x + 5) \: then \: other \: is$
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Answer 1

$\large\blue{\textsf{✩ Your Answer ✓ }}$

Heya mate, Here's your answer in the attachment..

Go through it very carefully.

$\small\bold{\textbf{\textsf{{\color{Purple}{Hope \: it \: helps}}}}}$

Answer 2

Answer:

Let (x-a) be the other factor.

Now, (x+5), (x-a) are factors of the quadratic equation x² + x - 20

$\huge\pink{\textsf{Thus,}}$

(x+5)(x−a)=x² + x - 20

$\huge{⟹}$ x² - ax + 5x - 5a = x² + x - 20

$\huge{⟹}$ x(5−a)−5a=x−20

$\small\red{\textsf{Now, considering the co-efficients of x on the both sides,}}$

5 - a = 1

$\huge{⟹}$ a = 5 - 1 = 4

Therefore the other factor is $\large\blue{\textsf{✓ (x−4)}}$

$\huge\mathtt\pink{\textsf{MissEleGant}}$