if one of the factor of x²x-20 is x+5 then te other
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x-4
Step-by-step explanation:
Let (x-a) be the other factor. Now, (x + 5), (x - a) are factors of the quadratic equation x² + x - 20 Thus,
(x+5)(x-a)=x² + x - 20
=> x² - ax + 5x -5a = x² + x - 20
=> x(5-a) - 5a = x - 20
Now, considering the co-efficients of x on the both sides,
5-a=1
=> a=5-1=4
Therefore the other factor is (x-4)
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