Question

If one of the factors of (5x^2 + 70x - 160) is (x - 2) Find the other factor​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Another factor is (5x+80).

Given:

• $5 {x}^{2} + 70x - 160$
• If (x-2) is a factor of polynomial.

To find:

• Find the another factor.

Solution:

Concept to be used:

• Divide the polynomial by its factor,then another factor will find as a quotient polynomial.

Step 1:

Let $p(x) = 5 {x}^{2} + 70x - 160$

and it's factor is $g(x) = x - 2$

Step 2:

Divide p(x) by g(x).

$\: \: \: \: \: \: x - 2 \: ) \: 5 {x}^{2} + 70x - 160 \: (5x + 80 \\ 5 {x}^{2} - 10x \\ ( - ) \: \: \: ( + ) \\ - - - - - - \\ 80x - 160 \\ 80x - 160 \\ ( - ) \: \: \: ( + ) \\ - - - - - \\ 0 \\ - - - - -$

Thus,

Another factor is (5x+80).

Learn more:

1) if (X + 2) is a factor of X⁵ - 4a²x + 2 X +2a+3 find a.

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2) One of the factors of (x³- 1) - (x - 1) is

x² + 1

x - 3

x-1

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