Question

If one of the factors of (5x2

+ 70x – 160) is (x – 2). Find the other factor.

Answer 1

Step-by-step explanation:

If one of the factors of

(x-2)=0

or, x=2

(5x2+ 70×2 – 160)

=(10+140-160)=0

=10+140-160

= -10

or others step

(5x2+ 70x – 160) =0

or, 10-70x=160

or, -70x=160-10

or, -70x= 150

or x= -(150/70)

x= -(15/7)

then

x-2

= -(15/7-2)

= -(15-14/7)

= -1/7

= - 0.1428

Answer 2

(−25x  

2

−1)+(1+5x)  

2

 

=−25x  

2

−1+1+25x  

2

+10x

=10x

So, 10x is a factor of itself.