If one of the factors of the expression x2 - ax + 5x - 5a is (x + 5), the other factor is:
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Answered by
6
let the other zeros be 'x'
x+5=0
x=(-5)
Product of zeros=Constant/coefficient of x^2
(-5)(x)=(-5a)
x=a.
Hence,other zeros=(a)
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Sahil kumar
Answered by
1
Step-by-step explanation:
x^2-ax+5x-5a
=x(x-a)+5(x-a)
=( x-a) (x+5)
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