Question

if one of the lines my^2+(1-m)^2xy-mx^2=0 is a bisector of angle between the lines xy=0 then m =​

Answer 1

Step-by-step explanation:

Angle bisectors of xy=0 are x+y=0 and x=y

my

2

+xy−m

2

xy−mx

2

=0

∴y(my+x)−mx(my+x)=0

∴(y−mx)(my+x)=0

Comparing y−mx=0 and my+x=0 with y=x and y=−x, we get m=±1