If one of the lines of my2 + (1 - m2)xv-mx2 = 0 is a bisector of the angle between
the lines xy = 0, then what is the value of m
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Answer:
m=±1
Explanation:
I think this is the answer i hope this helps, sorry if its wrong but i think its right...
my
2
+(1−m
2
)xy−mx
2
(my+x)(y−mx)=0
Therefore the lines are y=mx and y=
m
−x
...(i)
The angle bisectors of the xy=0 is y=x and y=−x
Comparing the slopes with the equations of the (i) we get
m=±1
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