Question

If one of the lines of my2 + (1 - m2)xv-mx2 = 0 is a bisector of the angle between
the lines xy = 0, then what is the value of m​

Answer 1

Answer:

m=±1

Explanation:

I think this is the answer i hope this helps, sorry if its wrong but i think its right...

my  

2

+(1−m  

2

)xy−mx  

2

 

(my+x)(y−mx)=0

Therefore the lines are y=mx and y=  

m

−x

​  

 ...(i)

The angle bisectors of the xy=0 is y=x and y=−x

Comparing the slopes with the equations of the (i) we get

m=±1