Question

If one of the mass is doubled and distance between them is trippled, then find the new
gravitational force between them.

Answer 1

Given :

Mass of the body ‘a’ = m

Mass of the body ‘b’ = M

Distance between two bodies = r

Gravitational constant = G

Therefore, gravitational force,

F = G*M*m / r² - (i)

Now, as the question says, one of the mass is doubled and the distance between the two bodies is trippled, so the new gravitational force is, F' = G*(2M)*m / (3r)²

Therefore, F' = 2G*M*m / 9r²

F' = 2/9 × G*M*m / r²

From equation (i)

F' = 2/9*F

$\bold{Hope\;it \; helps\;!}$