Question

If one of the member of Pythagorean triplet is 8 the other two are

Answer 1

For every natural number m>1

Pythagorean triplets are 2m, m²+1, m²-1

In which 2m is the smallest member.

2m=8

m= 4

m²+1= 4²+1= 16+1= 17

m²+1=17

m²- 1= 4²-1= 16-1= 15

m²-1= 15

The Pythagoreous triplets are 8,15 and 17.

Answer 2

8,15,17

a^2+b^2=c^2

8^2+15^2=17^2

64+225=289