Question

if one of the members of the pythagorean triplet is 2
a)m,m square+1

Answer 1

Answer:

other members are 1.73(approx) and 3.99(approx)

Step-by-step explanation:

it would be 2m , m square +1 instead of m,m square + 1 which means 2 carry the criteria m square - 1 according to this we can solve other members

we know that in a phythagorus theorem ,

(2m)^2 + (m^2 - 1)^2 = m^2+1

according to this one member is 2

let do by m^2 - 1

m^2 - 1 = 2

m^2 = 3

m = 1.73(appox)

then others are

2m = 2(1.73(appox)) = 3.46(approx)

m^2 + 1 = 1.73(approx)^2 + 1 = 3.9929(approx) or 3.99(approx)

so all members are 1.73(approx) and 3.99(approx)

then others are,