Question

if one of the number of Pythagorean triplet is 10 find the other two nembers (take 2M=10)​

Answer 1

$\huge\bold{\mathtt{Question⇒}}$

If one of the members of Pythagorean triplet is 10 find the other two nembers (take 2M=10).

$\huge\bold{\mathtt{Given⇒}}$

• One of the members of Pythagorean triplet is 10.

• 2M=10

$\huge\bold{\mathtt{To\:find⇒}}$

The other two nembers.

$\huge\bold{\mathtt{Solution⇒}}$

2M = 10

First we have to find the value of M.

2M = 10

➳ M = $\frac{10}{2}$

➳ M = 5

We know that a Pythagorean Triplet with M is

{2M, (M²-1), (M²+1)}

So, the triplet

= {2M, (M²-1), (M²+1)}

Substitute M with 5.

= {(2×5), (5²-1), (5²+1)}

= {10, (25-1), (25+1)}

= (10, 24, 26)

$\huge\bold{\mathtt{Hence⇒}}$

The triplet = (10, 24, 26)

Other two members = 24 and 26.

$\huge\bold{\mathtt{Therefore⇒}}$

The other two nembers of the Pythagorean triplet are 24 and 26.

$\huge\bold{\mathtt{Done}}$

$\large\bold{\mathtt{Hope\:this\:helps\:you.}}$

$\large\bold{\mathtt{Have\:a\:nice\:day.}}$